问题描述
Given two binary strings, return their sum (also a binary string).
For example,
a = “11”
b = “1”
Return “100”
code
/*
注意
多一位
111+1=1000
110+1=【0111】=111
0+0=0
*/
public class Solution {
public String addBinary(String a, String b) {
char[] chara = a.toCharArray();
char[] charb = b.toCharArray();
int lena = chara.length;
int lenb = charb.length;
StringBuilder str = new StringBuilder();
char carry = '0';
int i = lena-1;
int j = lenb-1;
char[] ch = new char[2];
while(lena >= 0 || lenb >= 0) {
lena--;
lenb--;
char a1,b1;
if(i<0) a1 = '0';
else {
a1 = chara[i];
}
if(j<0) b1 = '0';
else {
b1 = charb[j];
}
ch = getSumBinary(a1, b1, carry);
str.insert(0, ch[0]);
carry = ch[1];
i--;
j--;
}
String out = str.toString().replaceAll("^(0)+", "");
if(out.equals("")) out = "0";
return out;
}
public char[] getSumBinary(char a,char b,char c) {
int value = a+b+c;
char[] ch = new char[2];
switch(value) {
case '0'+'0'+'0': ch[0]='0';ch[1]='0';break;
case '0'+'0'+'1': ch[0]='1';ch[1]='0';break;
case '0'+'1'+'1': ch[0]='0';ch[1]='1';break;
case '1'+'1'+'1': ch[0]='1';ch[1]='1';break;
}
return ch;
}
}